签到题，用两个数组分别存储一下即可

#include <bits/stdc++.h>
using namespace std;
int a[1010], b[1010], aa = 0, bb = 0, maxa = -1, maxb = -1;
int main() {
    int n;
    cin >> n;
    while (n--) {
        int t;
        cin >> t;
        if (t % 2 == 1)
            a[aa++] = t;
        else
            b[bb++] = t;
    }
    cout << aa << endl;
    if (aa > 0) {
        cout << a[0];
        for (int i = 1; i < aa; i++) cout << " " << a[i];
        cout << endl;
    }
    cout << bb << endl;
    if (bb > 0) {
        cout << b[0];
        for (int i = 1; i < bb; i++) cout << " " << b[i];
    }
    return 0;
}